Calculate earth's magnetic field at a place where angle of dip `delta` is `60^(@)` and horizontal component of earth's magnetic field is 0.3 G

Explanation

Given , `B_(H) = 0.3 G , delta= 60^(@)`
`B_(H) = B_(e) cos delta`
` B_(e) = (B_(H))/(cos delta)`
`= (0.3)/(cos 60^(@))`
`B_(e) = 0.6 G`