What is the magnitude of the equatorial and axial fields due to a bar manget of length `5*0cm` at a distance of `50cm` from its mid-point? The magnetic moment of the bar magnet is `0*40Am^2`.

Explanation

`(i) B= (mu_(0))/(4pi) (2M)/(r^(3)) = 10^(-7) xx (2 xx 0.4)/((0.5)^(3)) = 10^(-7) xx (8 xx 10^(-1))/(125 xx 10^(-3))`
`B = 10^(-8) xx 10^(-3) xx (8)/(125) = 0.064 xx 10^(-5) = 6.4 xx 10^(-7) T`
(ii) `B = (mu_(0))/(4pi) (M)/(r^(3)) = 10^(-7) xx (0.4)/((0.5)^(3)) = 3.2 xx 10^(-7) T`