A magnetising field of `1500""(A)/(m)` produces a magnetic flux density of `0.48 Wb//m^(2) ` in a iron bar . Calculate permeability of iron bar used .

Explanation

`mu = (B)/(H) = (0.48)/(1500)`
`= (48 xx 10^(-2))/(15 xx 10^(-2))`
= `(48)/(15) xx 10^(-4) (Wb)/(m^(2)) xx (m)/(A)`
`= 3.2 xx 10^(-4) ` Wb/mA