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Find the critical angle of a denser medi...

Find the critical angle of a denser medium of refractive index 1.65 for its interface with air `(sin^(-1) (0.6061) 37^(@).18'`).

Text Solution

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`mu = (1)/(sin C)`
`sin C = (1)/(1.65)`
= 0.6061
`c = 37^(@).18'`
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