A parallel incident beam falls on a solid glass sphere at near normal incidence.Show that the image in terms of the index of refractive `mu` and the sphere of radius R is given by
`(R(2-mu))/(2(mu-1))`

A parallel incident beam falls on a solid glass sphere at normal incidenc. Prove that the distance of the fianll image after two refractions is at a distance (2-mu)//2(mu-1)a from the outer edge of the sphere. Refractive index of the sphere is mu and radius of the sphere is a.

A narrow parallel beam of light falls on a glass sphere of radius R and refractive index mu at normal incidence. The distance of the image from the outer edge is given by-

If angle of incidence is twice the angle of refraction in a medium of refractive index mu , then angle of incidence is

A ray of light falls on a glass plate of refractive index mu=1.5 . What is the angle of incidence of the ray if the angle between the reflected and refracted rays is 90^@ ?

A horizontal ray of light is incident on a solid glass sphere of radius R and refractive index mu . What is net deviation of the beam when it emerged from the other side of the sphere?

A ray of light ravels from a liquid of refractive index mu to air. If the incident beam is rotating at a rate omega , what is the angular sped of the refracted beam at the instant the angle of incidence is 30^@ ? (Given mu=sqrt (2), omega =1//sqrt(6) rad s^(-1) ).

A narrow pencil of parallel light is incident normally on a solid transparent sphere of radius r. What should be the refractive index if the pencil is to be focussed (a) at the surface of the sphere, (b) at the centre of the sphere.

Light rays from a source are incident on a glass prism of index of refraction mu and angle of prism alpha At near normal incidence, the angle of deviation of the emerging rays is