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If de Broglie wavelength of an electron ...

If de Broglie wavelength of an electron is 0.5467 Å, find the kinetic energy of electron in eV. Given `h=6.6xx10^(-34)` Js , e=`1.6xx10^(-19)` C, `m_e=9.11xx10^(-31)` kg.

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`E_k=1/2h^2/(mlambda^2)=1/2xx((6.6xx10^(-34))^2)/(9.11xx10^(-31)xx(0.5467xx10^(-10))^2)J`
`E_k` in eV =`1/2xx((6.6xx10^(-34))^2)/((9.11xx10^(-31))xx(1.6xx10^(-19))xx(0.5467xx10^(-10))^2)`=500 eV
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