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How much (in %) the binding energy of el...

How much (in %) the binding energy of electron differs in hydrogen atom when mass of nucleus is taken into account of infinite value (i.e., nucleus is motionless ) and of infinite value.

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When we take nucleus of hydrogen atom stationary (i.e. of infinite mass ) then binding energy of electron
`E_b=(e^4m)/(8epsilon_0^2h^2)`
and if mass of nucleus is taken into account finite then binding energy
`E'_b=(e^4mu)/(8epsilon_0^2h^2)`
Where `mu="mM"/"m+M"` , m= mass of electron , M=mass of nucleus
`therefore` % change in binding energy of electron
`(DeltaE)/E_bxx100=(E_b-E_a)/E_bxx100`
`=[1- 1/(1+m/M)]xx100`
`=m/Nxx100`
`=(9.1xx10^(-31))/(1.67xx10^(-27))xx100=0.05 %`
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