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Assuming the nuclei to be spherical in s...

Assuming the nuclei to be spherical in shape, how does the surface area of a nucleus of mass number `A_1` compare with that of a nucleus of mass number `A_2`?

Text Solution

Verified by Experts

The correct Answer is:
`S_1/S_2=(A_1/A_2)^(2//3)`
`S=4piR^2 prop A^(2//3)`
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