The parallax of a heavenly body measured...

The parallax of a heavenly body measured from tow points diametrically opposite on equator of earth is 2.0 minute. If radius of earth is 6400 km, calculate distance of heavenly body.

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Angle of parallax `theta`=2 minute
`=2xx(1/60)^@`
`rArr theta=2 xx 1/60xxpi/180` rad [ `because1^@=pi/180` rad ]
`theta=pi/5400` rad
From parallax method
`BP="AB"/theta`
`rArr BP="Diameter of earth "/theta`
`rArr BP=(2xx6400)/((pi/5400))` km
`rArr BP=2.2xx10^7` km
`=2.2xx10^10` m

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