Find the area enclosed by the ellipse `(x^(2))/(25) + (y^(2))/(16) = 1` .

Explanation

To find the area enclosed by the ellipse given by the equation \(\frac{x^2}{25} + \frac{y^2}{16} = 1\), we can follow these steps:

### Step 1: Identify the parameters of the ellipse
The standard form of the ellipse is given by \(\frac{x^2}{a^2} + \frac{y^2}{b^2} = 1\).

From the equation \(\frac{x^2}{25} + \frac{y^2}{16} = 1\):
- \(a^2 = 25\) which gives \(a = 5\)
- \(b^2 = 16\) which gives \(b = 4\)
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