Let the two foci of an ellipse be `(-1, 0) and (3, 4)` and the foot of perpendicular from the focus `(3, 4)` upon a tangent to the ellipse be `(4, 6)`. The foot of perpendicular from the focus `(-1, 0)` upon the same tangent to the ellipse is

The foot of the perpendicular from the point (2,4) upon x+y=4 is

The locus of foot of perpendicular from the focus upon any tangent to the parabola y^(2) = 4ax is

The foot of the perpendicular from the point (2, 4) upon x + y= 4 is:

Product of perpendiculars drawn from the foci upon any tangent to the ellipse 3x^(2)+4y^(2)=12 is

Show that the locus of the foot of the perpendicular from the focus to the tangent of the parabola

The locus of the foot of perpendicular from my focus of a hyperbola upon any tangent to the hyperbola is the auxiliary circle of the hyperbola. Consider the foci of a hyperbola as (-3, -2) and (5,6) and the foot of perpendicular from the focus (5, 6) upon a tangent to the hyperbola as (2, 5). The point of contact of the tangent with the hyperbola is

The locus of the foot of perpendicular from my focus of a hyperbola upon any tangent to the hyperbola is the auxiliary circle of the hyperbola. Consider the foci of a hyperbola as (-3, -2) and (5,6) and the foot of perpendicular from the focus (5, 6) upon a tangent to the hyperbola as (2, 5). The point of contact of the tangent with the hyperbola is