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sin^(- 1)(- 1/2)...

`sin^(- 1)(- 1/2)`

Text Solution

Verified by Experts

The correct Answer is:
`-pi/6`
Range of `sin^(-1)` is `[pi/2,pi/2]`.
`sin^(-1)(-1/2)=theta rArr sintheta=-1/2=sin(-pi/6)`
`rArr theta=-pi/6`
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