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sin[cos^(-1)(3/5)]...

`sin[cos^(-1)(3/5)]`

A

`3/4`

B

`4/5`

C

`3/5`

D

none of these

Text Solution

Verified by Experts

The correct Answer is:
B
Let `cos^(-1)3/5=x`, where `x in [0,pi]`. Then, `cos x=3/5`.
`therefore` since `x in [0,pi], sin x gt 0`.
`therefore sinx=sqrt(1-9/25)=sqrt(16/25)=4/5 rArr sin(cos^(-1)3/5)=4/5`.
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