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Sin[pi/3-sin^(-1)(-1/2)]...

`Sin[pi/3-sin^(-1)(-1/2)]`

A

`1`

B

`0`

C

`-1/2`

D

none of these

Text Solution

Verified by Experts

The correct Answer is:
A
`sin{pi/3-sin^(-3)(-1/2)}=sin{pi/3+sin^(-1)1/2}=sin(pi/3+pi/6)=sinpi/2=1`.
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