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Find the value of: tan^(-1)[2cos(2sin^(-...

Find the value of: `tan^(-1)[2cos(2sin^(-1)(1/2))]`

A

`pi/3`

B

`pi/4`

C

`(3pi)/4`

D

`(2pi)/3`

Text Solution

Verified by Experts

The correct Answer is:
B
`tan^(-1){2cos(2sin^(-1)1/2)}=tan^(-1){2cos(2 xx pi/6)}=tan^(-1){2cospi/3}=tan^(-1){2 xx 1/2}=tan^(-1)1=[i/4`.
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