Vertex of the parabola with focus (a, b) and directrix `x/a+y/b=1`will be be

The equation of the parabola with focus (a, b) and directrix x/a+y/b=1 is given by

The equation of the parabola with focus (a,b) and directrix (x)/(a)+(y)/(b)=1 is given by

The vertex of parabola whose focus is (2,1) and directrix is x - 2y + 10 = 0 is

The vertex of parabola whose focus is (2,1) and directrix is x - 2y + 10 = 0 is

Equation of parabola whose focus is(a,b) and directrix is (x)/(a)+(y)/(b)=1

If the vertex of the parabola is (3,2) and directrix is 3x+4y-(19)/(7)=0, then find the focus of the parabola.

If the vertex of the parabola is (3,2) and directrix is 3x+4y-(19)/7=0 , then find the focus of the parabola.

Find the quation of the following parabolas. Focus (a,b) , directrix (x)/(a)+(y)/(b)=1

If the line x+y-1=0 is a tangent to a parabola with focus (1,2) at A and intersect the directrix at B and tangebt at vertex at C respectively,then AC.BC is equal to

Find the focus and the equation of the parabola whose vertex is (6, -3) and directrix is 3x-5y+1=0