`sinx+cos(x+3 0^(@))=0,0^(@)ltxlt36 0^(@)`

If (sinx)/(1+cosx)+(sinx)/(1-cosx)=4,and0^(@)ltxlt90^(@) , then find the value of x .

If sinx - cosx = 0, 0^@ltxlt90^@ then the value of (secx +cosec x)^2 is: sinx - cosx = 0, 0^@ltxlt90^@ तो (secx +cosec x)^2 का मान है:

If f(x)={((sinx+cosx)^(cosecx),-(pi)/2ltxlt0),(a,x=0),((e^(1/x)+e^(2/x)+e^(3/x))/(ae^(-2+1/x)+be(-1+3/x)), 0ltxlt(pi)/2):} is continuous at x=0 then

" Prove that "(cos9^(0)+sin9^(0))/(cos9^(0)-sin9^(0))=cot36^(@)

The verticles of a triangle are (0,0) , (x cosx) and (sin^(3)x,0) , where 0ltxlt(pi)/(2) . The maximum area for such a triangle in sq units is

" If "sin^(2)x+sin x cos x-6cos^(2)x=0" and "-(pi)/(2)ltxlt0," then value of "cos2x" is " -3/5 3/5 -4/5 4/5

If 2cos^(2)x+3sinx-3=0,0lexle180^(@) , then x =

If 2cos^(2)x+3sinx-3=0,0lexle180^(@) , then x =