Let N be the greatest number that will divide 1305 , 4665 and 6905 Ieaving the same remainder in each case The sum of the digits in N is

Explanation

Here, `N` will be the `H.C.F.` of difference between numbers,
`4665-1305` and `6905-4665`.

`N` is the H.C.F. of `3360` and `2240`.

`3360 = 1120**3`

`2240 = 1120**2`

So, `H.C.F.` of these two number is `1120`.

So, `N = 1120`.

`:.` Sum of digits of `N = 1+1+2+0 = 4`