`=zgeqy=8/7y^2 1/3z^2`

= z> = y = (8) / (7) y ^ (2) (1) / (3) z ^ (2)

Simplify: 2-3z^(2)+5yz+7y^(2)-8+z^(2)-6yz-9y^(2)+1-2z^(2)-2yz-y^(2)

Find x,y,z using Cramer's Rule,if 5/x-7/y+1/z=11,6/x-8/y-1/z=15,3/x+2/y-6/z=7.

If x prop y and y prop z , then prove that (x^7+y^7 +z^7) prop (x^5y^2 +x^3z^4 +y^5z^2)

The intersection of the spheres x^2+y^2+z^2+7x-2y-z=13a n dx^2+y^2+z^2-3x+3y+4z=8 is the same as the intersection of one of the spheres and the plane a. x-y-z=1 b. x-2y-z=1 c. x-y-2z=1 d. 2x-y-z=1