Calculate the amount of heat (in calories) required to convert `5 gm` of ice at `0^(@)C` to steam at `100^(@)C`

Heat required to convert 1 g of ice at 0^(@)C into steam at 100 ^(@)C is

Heat required to convert 1 g of ice at 0^(@)C into steam at 100 ^(@)C is

The amount of heat (in calories) required to convert 5g of ice at 0^(@)C to steam at 100^@C is [L_("fusion") = 80 cal g^(-1), L_("vaporization") = 540 cal g^(-1)]

The amount of heat (in calories) required to convert 5g of ice at 0^(@)C to steam at 100^@C is [L_("fusion") = 80 cal g^(-1), L_("vaporization") = 540 cal g^(-1)]

How many calories of heat will be required to convert 1 g of ice at 0^(@)C into steam at 100^(@)C

What is the amount of heat required (in calories) to convert 10 g of ice at -10^(@)C into steam at 100^(@)C ? Given that latent heat of vaporization of water is "540 cal g"^(-1) , latent heat of fusion of ice is "80 cal g"^(-1) , the specific heat capacity of water and ice are "1 cal g"^(-1).^(@)C^(-1) and "0.5 cal g"^(-1).^(@)C^(-1) respectively.

What is the amount of heat required (in calories) to convert 10 g of ice at -10^(@)C into steam at 100^(@)C ? Given that latent heat of vaporization of water is "540 cal g"^(-1) , latent heat of fusion of ice is "80 cal g"^(-1) , the specific heat capacity of water and ice are "1 cal g"^(-1).^(@)C^(-1) and "0.5 cal g"^(-1).^(@)C^(-1) respectively.

Calculate the amount of heat required to convert 10 gm of ice at 0^@C to steam at 100^@C .