What should be the length of steel and copper rods at `0^(@)C` that the length of steel rod is 5 cm longer than copper at all termperature? Given `alpha_(Cu) = 1.7 xx 10^(5) .^(@)C^(-1)` and `alpha_(steel) = 1.1 xx 10^(5) .^(@)C^(-1)`.

What should be the lengths of steel and copper rod so that the length of steel rod is 10 cm longer than the copper rod at all the temperatures. Coefficients of linear expansion for copper and steel are alpha_(Cu)=1.7xx10^(-5)""^(@)C^(-1)andalpha_("steel")=1.1xx10^(-5)""^(@)C^(-1)

What must be the lengths of steel and copper rods at 0^(@)C for the difference in their lengths to be 10 cm at any common temperature? (alpha_(steel)=1.2xx10^(-5).^(@)K^(-1)and alpha_("copper")=1.8xx10^(-5).^(@)K^(-1))

What must be the lengths of steel and copper rods at 0^(@)C for the difference in their lengths to be 10 cm at any common temperature? (alpha_(steel)=1.2xx10^(-5).^(@)K^(-1)and alpha_("copper")=1.8xx10^(-5).^(@)K^(-1))

What should be the length of steel abd copper rods at 0^@C so that the difference in their lengths is 5.0 cm at all temperatures. Coefficient of linear expansion of copper is 1.7 xx 10^(-5) //^@ C and that of steel is 1.1 xx 10^(-5) //^@ C .

The length of the steel rod which would have the same difference in length with a copper rod of length 24cm at all temperatures. (alpha_("copper") = 18 xx 10^(-6) K^(-1) alpha_("steel") = 12 xx 10^(-6) k^(-1)) is -

A fine steel wire of length 4 m is fixed rigidly in a heavy brass frame as ashown in figure . It is just taut at 20^(@)C . The tensile stress developed in steel wire it whole system is heated to 120^(@)C is :- ( Given alpha _("brass") = 1.8 xx 10^(-5) .^(@)C^(-1), alpha_("steel") = 1.2 xx 10^(-5) .^(@)C , Y_("steel") = 2 xx 10^(11) Nm^(-2), Y_("brass")= 1.7xx10^(7) Nm^(-2) )

A fine steel wire of length 4 m is fixed rigidly in a heavy brass frame as ashown in figure . It is just taut at 20^(@)C . The tensile stress developed in steel wire it whole system is heated to 120^(@)C is :- ( Given alpha _("brass") = 1.8 xx 10^(-5) .^(@)C^(-1), alpha_("steel") = 1.2 xx 10^(-5) .^(@)C, Y_("steel") = 2 xx 10^(11) Nm^(-2), Y_("brass")= 1.7xx10^(7) Nm^(-2) )