Consider the situation of the previous problem, if the mirror reflects only 64% of the light energy falling on it, what will be the ratio of the maximum to the minimum intensity in the interference pattern observed on the screen ?

A long horizontal slit is placed 1 mm above a horizontal plane mirror. The interference between the light coming directly from the slit and the after reflection is seen on a screen 1 m away from the slit. If the mirror reflects only 64% of the light falling on it, the ratio of the maximum to the minimum intensity in the interference pattern observed on the screen is

A long horizontal slit is placed 1 mm above a horizontal plane mirror. The interference between the light coming directly from the slit and the after reflection is seen on a screen 1 m away from the slit. If the mirror reflects only 64% of the light falling on it, the ratio of the maximum to the minimum intensity in the interference pattern observed on the screen is

Two sources with intensity 9 : 4 interfere in a medium. Then find the ratio of maximum to the minimum intensity in the interference pattern.

If ratio of intensities of two waves is 64 : 9. Calculate the ratio of maximum and minimum intensity in the interference pattern formed by these two waves.

Two sources with intensity 9I_(0) and 4I_(0) interfere in a medium. Then find the ratio of maximum to the minimum intensity in the interference pattern.

Two waves, whose intensities are 9,16 are made to interference. The ratio of maximum and minimum intensities in the interference pattern is -