`((7k)/(l))^12=((49k)/(7l))^(2x+6)`

L_(1):(x+1)/(-3)=(y-3)/(2)=(z+2)/(1),L_(2):(x)/(1)=(y-7)/(-3)=(z+7)/(2) The lines L_(1) and L_(2) are -

L_(1):(x+1)/(-3)=(y-3)/(2)=(z+2)/(1),L_(2):(x)/(1)=(y-7)/(-3)=(z+7)/(2) The lines L_(1) and L_(2) intersect at the point

L_(1):(x+1)/(-3)=(y-3)/(2)=(z+2)/(1),L_(2):(x)/(1)=(y-7)/(-3)=(z+7)/(2) Equation of plane containinng L_(1) and L_(2) is -

L_(1):(x+1)/(-3)=(y-3)/(2)=(z+2)/(1),L_(2):(x)/(1)=(y-7)/(-3)=(z+7)/(2) The lines L_(1) and L_(2) are -

If I=int(5x^(8)+7x^(6))/((x^(2)+1+2x^(7))^(2))dx then l is equal to

((4k^8l^2m^6)/(-5k^3l^5m^0))^4

The centre of mass of a non uniform rod of length L whose mass per unit length lambda = K x^2 // L where K is a constant and x is the distance from one end is (A) (3L)/(4) (B) (L)/(8) (C) (K)/(L) (D) (3K)/(L)

prod_ (k = 1) ^ (6) (sin ((2k pi) / (7)) - i cos ((2k pi) / (7))) =