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The value of the expression (1-ax)(1+ax)...

The value of the expression `(1-ax)(1+ax)^(-1)(1+bx)^(1/2)(1-bx)^(-1/2)` at `x=a^(-1)(2a/b-1)^(1/2)`, is: a. dependent on both `a` and `b` b.;`1` c. ;`-1`

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{:(ax + by = 1),(bx + ay = ((a + b)^(2))/(a^(2) + b^(2))-1):}

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