M is a metal that forms an oxide `M_(2)O,(1)/(2)M_(2)O rarr M+(1)/(4)O_(2) Delta H=120` K. Cal. When a sample of metal M reacts with one mole of oxygen what will be the `Delta H` in that case

M is a metal which forms an oxide, M_(2)O and (1)/(2) M_(2)O(s) rarr M(s) + (1)/(4) O_(2)(g), Delta H = 90 kJ mol^(-1) When a sample of the metal M reacts with 1 mole of O_(2)(g) to form M_(2)O , DeltaH for the reaction is :

MgSO_(4(s)) + H_(2)O rarr MgSO_(4(aq)), Delta H = - 84K . Cals, Delta H of the reaction is known as

DeltaS_(sur) for H_(2)+1//2O_(2) rarr H_(2)O, Delta H = -280 KJ at 400 K is

In the formation of superoxide M+O_(2)toMO_(2), the metal M is

C+O_(2)rarr CO_(2), Delta H = -94 K.cal, CO+(1)/(2)O_(2) rarr CO_(2), Delta H = -67.7 K.cal . On the basis of the above data, the heat of formation of 'CO' is

A metal M of atomic mass A forms an oxide of the formula M_(x)O_(y) . The equivalent mass of metal is given by

M + 2H_(2)O rarr M(OH)_(2) + H_(2) Which metal among the following cannot undergo this reacton at high temperatures ?

M + 2H_(2)O rarr M(OH)_(2) + H_(2) Which metal among the following cannot undergo this reacton at high temperatures ?