The emf of a cell is 2 V. When the terminals of the cell is connected to a resistance `4Omega`. The potential difference across the terminals, if internal resistance of cell is `1Omega` is

The emf of a daniel cell is 1.08 V. When the terminals of the cell are connected to resistance of 3Omega , the potential difference across the terminals is found to be 0.6 V. Then , the internal resistance of the cell is

The emf of a daniel cell is 1.08 V. When the terminals of the cell are connected to resistance of 3Omega , the potential difference across the terminals is found to be 0.6 V. Then , the internal resistance of the cell is

The emf of a daniel cell is 1.08 V. When the terminals of the cells are connected to a ressitance of 3Omega , the potential difference across the terminals is found to be 0.6 V. Then the internal resistance of the cell is

A cell of emf E is connected across a resistance R. The potential difference between the terminals of the cell is found to be V. The internal resistance of the cell must be -