In figure, BC is a diameter of the circle and `angleBAO=60^(@)." Then", angleADC`is equal to

In the adjoining figure, BP is the diameter of the circle. If angle ABP=60^(@) , then find angle AQB .

ABCD is a cyclic quadrilateral such that AB is a diameter of the circle circumscribing it and angleADC=140^(@)," than "angleBAC is equal to

ABCd is a cyclic quadrialteral such that AB is a diameter of the circle circumscribing it and angleADC = 140^@, then angleBAC is equal to

ABCD is a cyclic quadrilateral such that AB is the diameter of the circle circumscribing it and angleADC = 150^(@) . Then. angleBAC is equal to:

ABCD is a cyclic quadrilateral such that AB is a diameter of the circle circumscribing it and angleADC=140^(@)," than "angleBAC is equal to

In the given figure, AB is the diameter of the circle, angleADC = 120^(@) . Find angleCAB :

If AOB is a diameter of the circle and AC=BC, then angle CAB is equal to

If AOB is a diameter of the circle and AC=BC, then angle CAB is equal to

In the given figure, O is the centre of the circle and angleAOC = 100^(@) . Find the ratio of angleADC : angleABC :