In `DeltaABC` orthocentre is (6,10) circumcentre is (2,3) and equation of side BC is `2x+y=17`.Then the radius of the circumcircle is

In Delta ABC orthocentre is (6,10) circumcentre is (2,3) and equation of side BC is 2x+y=17. Then the radius of the circumcircle is

If the sides of a triangle are 8,15,17 then the radius of its circumcircle is

If the sides of a triangle ABC are 6,8,10 units, then the radius of its circumcircle is

If the Let ABC be a triangle having orthocentre and circumcentre at (9,5) and (0, 0) respectively.equation of side BC is 2x-y=10, then find the possible coordinates of vertex A .

IF the sides of a triangle ABC are 6,8,10 unit , then the radius of its circumcentre is

Let ABC be a triangle having orthocentre and circumcentre at (9,5) and (0,0) respectively. If the equation of side BC is 2x – y = 10 , then find the possible co- ordinate of vertex A: O (1,9) O (9, 1) O (9,5) O (7,6)

The equation to the side "BC" of " Delta ABC " is " x+5=0 " .If " (-3,2) " is the orthocentre and "(0,0)" is the circumcentre then radius of the circle is

Let the circumcentre of DeltaABC is S (-1,0) and the midpoints of sides AB and AC are E(1,-2) and F(-2,1) respectively , then the equation of the circumcircle of DeltaABC us