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[" A "1000m" long rod of density "10.0ti...

[" A "1000m" long rod of density "10.0times10^(@)kg/m^(3)" and having young's modulus "Y],[" end .It is hammered at the other free end as shown in the figre.The longitudin "],[" reflected and again returns to the left end.How much time (in sec) the pulse will "],[qquad hat omega rarr square]

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A 1000 m long rod of density 10.0 xx 10^(4) kg//m^(3) and having young's modulus Y=10^(11) Pa , is clamped at one end. It is hammered at the other free end as shown in the figure. The logitudinal pulse goes to right end, gets reflected and again returns to the left end. How much time (in sec) the pulse take to go back to initial point ? .

A 1000 m long rod of density 10.0 xx 10^(4) kg//m^(3) and having young's modulus Y=10^(11) Pa , is clamped at one end. It is hammered at the other free end as shown in the figure. The logitudinal pulse goes to right end, gets reflected and again returns to the left end. How much time (in sec) the pulse take to go back to initial point ? .

A 1000 m long rod of density 10.0 xx 10^(4) kg//m^(3) and having young's modulus Y=10^(11) Pa , is clamped at one end. It is hammered at the other free end as shown in the figure. The logitudinal pulse goes to right end, gets reflected and again returns to the left end. How much time (in sec) the pulse take to go back to initial point ? .

A 100 - m long rod of density 10.0 xx 10^(4) kg//m^(3) and having Young's modulus Y = 10^(11) Pa , is clamped at one end . It is hammered at the other free end. The longitudinal pulse goes to right end , gets reflected and again returns to the left end . How much time the pulse take to go back to initial point.

A 100 - m long rod of density 10.0 xx 10^(4) kg//m^(3) and having Young's modulus Y = 10^(11) Pa , is clamped at one end . It is hammered at the other free end. The longitudinal pulse goes to right end , gets reflected and again returns to the left end . How much time the pulse take to go back to initial point.

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