In a capacitor of capacitance `20 muF`,the distance between the plates is `2 mm`. If a dielectirc slab of width `1 mm` and dielectric constant `12` is inserted between the plates, then the new capacitance is

In a capacitor of capacitance 20muF , the distance between the plates is 2 mm. If a dielectric slab of width 1 mm and dielectric constant 2 is inserted between the plates, what is the new capacitance?

A parallel capacitor of capacitance C is charged and disconnected from the battery. The energy stored in it is E . If a dielectric slab of dielectric constant 6 is inserted between the plates of the capacitor then energy and capacitance will become.

A parallel capacitor of capacitance C is charged and disconnected from the battery. The energy stored in it is E . If a dielectric slab of dielectric constant 6 is inserted between the plates of the capacitor then energy and capacitance will become.

A parallel state air capacitor has capacitance of 100 muF . The plates are at a distance d apart. If a slab of thickness t (t le d) and dielectric constant 5 is introduced between the parallel plates, then the capacitance can be

When a sheet of dielectric is inserted between the two plates of a capacitor, its capacitance

A parallel plate capacitor has a capacitance of 100muF . The plates are at a distance d apart. A slab of thickness t(t = d) and dielectric constant 5 is introduced between the parallel plates. Then capacitance can be,

A parallel-plate of capacitor of capacitance 5mu F is connected in a battery of emf 6V. The separation between the plate is 2mm.(a) Find the charge on the positive plate.(b) find the eletric field between the plate.(c) A dielectric slab of thickness 1 mm and dielectric constant 5 is inserted into the gap to occupy the lower half of it.Find the capacitance of the new combination .(d)How much charge has flow n through the battery after the slab is inserted?