The ratio of de-Broglie wave length of a photon and an electron of mass 'm' having the same kinetic energy E is: (Speed of light=c)

The ratio of the wavelengths of a photon and that of an electron of same energy E will be [m is mass of electron ]

An electron (of mass m) and a photon have the same energy E in the range of few eV.The ratio of the de-Broglie wavelength associated with the electron and the wavelength of the photon is (c=speed of light in vaccum)

The de-Broglie wavelength of a photon is the same as the wavelength of electron, show that kinetic energy of photon is (2mclambda)/h times the kinetic energy of electron, where m is the mass of electron and c is the velocity of light.

De Broglie wavelength of a body of mass m and kinetic energy E is given by

The wavelenths gamma of a photon and the de-Broglie wavelength of an electron have the same value.Find the ratio of energy of photon to the kinetic energy of electron in terms of mass m, speed of light and planck constatn

The wavelenths gamma of a photon and the de-Broglie wavelength of an electron have the same value.Find the ratio of energy of photon to the kinetic energy of electron in terms of mass m, speed of light and planck constatn

An electron & a photon have same energy E. Find the ratio of de Broglie wavelength of electron to wavelength of photon. Given mass of electron is m & speed of light is C