At what depth below the surface of earth, value of accelaration due to gravity is same as the value at height `h =R1, where R is the radius of earth.

At what depth below the surface of earth the acceleration due to gravity becomes one-third of its value at the surface of earth ?

The depth at which the value of acceleration due to gravity is 1/n times the value at the surface, is (R=radius of the earth)

Calculate the depth below the surface of the earth where acceleration due to gravity becomes half of its value at the surface of the earth . Radius of the earth = 6400 km.

At what depth below the surface of the earth acceleration due to gravity will be half its value at 1600 km above the surface of the earth ?

At what depth below the surface of the earth acceleration due to gravity will be half its value at 1600 km above the surface of the earth ?

At a height of 10 km above the surface of earth, the value of acceleration due to gravity is the same as that of a particular depth below the surface of earth. Assuming uniform mass density of the earth, the depth is,

At what height above the earth surface, the acceleration due to gravity will be half that on the surface of earth ? Suppose R is the radius of earth.

The depth d , at which the value of acceleration due to gravity becomes 1/n times the value at the surface is (R = radius of the earth)

The depth d , at which the value of acceleration due to gravity becomes 1/n times the value at the surface is (R = radius of the earth)