If `x^y =y^x` then `(x/y)^(x/y) = x^(x/y - k)` where k =

If xy(x+y)=k," then: "x(x+2y)(dy)/(dx)=

If x^3y^9=(x+y)^k and x(dy)/(dx)=y then k =

If x + y + z = 0 , then ( x + y - z)^(3) + ( y + z - x)^(3) + (z + x - y) ^(3) = k (xyz) , where k is equal to :

If (x-y) e^((x)/(x-y)) =k ,then (dy)/(dx) =

If y = 2x + k " touches " x^(2) + y^(2) - 4x - 2y = 0 , then k=

If x,y,z are in A.P.then (x+2y-z)(2y+z-x)(z+x-y)=kxyz, where k in N, then k is equal to

Let (x)^(k) + (y)^(k) = (a)^(k) where a, k > 0 and (dy/dx) +(y/x)^(1/3) = 0 then find k

If the solution of the differential equation (1+e^((x)/(y)))dx+e^((x)/(y))(1-(x)/(y))dy=0 is x+kye^((x)/(y))=C (where, C is an arbitrary constant), then the value of k is equal to