If `(cos(A-B))/(cos(A+B))+cos(C+D)/(cos(C-D) )=0` Prove that `tanAtanBtanCtanD=-1`

If (cos(A-B))/("cos"(A+B))+("cos"(C+D))/("cos"(C-D))=0,\ prove tht tanAtanBtanCtanD=-1

If (cos(A-B))/(cos(A+B))+(cos(C+D))/(cos(C-D))=0, prove tht tan A tan B tan C tan D=-1

(cos(A-B))/(cos(A+B))+cos(C+D)/(cos(C-D))=0 => tan A tan B tan C tan D =

If (cos (AB)) / (cos (A + B)) + (cos (C + D)) / (cos (CD)) = 0 Prove that tan A tan B tan C tan D = -1

Solve the following: If (frac(cos(A+B))(cos(A-B)))=(frac(sin(C+D))(sin(C-D))) prove that tanA.tanB.tanC+tanD=0

(cos(A+B))/(cos(A-B))+(cos(C-D))/(cos(C+D))=0rArr cot A cot B cot C=

If ( cos (A+B))/( cos (A-B)) =( sin (C+D))/( sin (C -D)) then prove that tan A tan B tan C + tan D=0 ................. A) 0 B) -1 C) sqrt3 D) 1

(cos (AB)) / (cos (A + B)) + (cos (C + D)) / (cos (CD)) = 0rArr tan A tan B tan C tan D =

(cos(A+B))/(cos(A-B))+(cos(C-D))/(cos(C+D))=0rArr cot A cot B cot C cot D=

If cos (A + B) sin (C + D)= cos (A - B) sin (C- D), prove that tanAtanBtanC = tanD