`R r(sinA+sinB+sinC)=Delta`

In DeltaABC,sqrt(rr_1r_2r_3)/(2Rr(sinA+sinB+sinC)) =

If P is the circumcentre of an acute angled triangle ABC with circumredius R. D is the midpoint of BC. Show that the perimetre of triangleABC = 2R(sinA + sinB + sinC) .

If in a triangle ABC, Rr(sinA+sinB+sinC)=96 then the square of the area of the triangle ABC is…….

If in a triangle ABC, Rr(sinA+sinB+sinC)=96 then the square of the area of the triangle ABC is…….

In triangle A B C ,(sinA+sinB+sinC)/(sinA+sinB-sinC) is equal to

In triangle ABC, (sinA+sinB+sinC)/(sinA+sinB-sinC) is equal to

In triangle ABC, (sinA+sinB+sinC)/(sinA+sinB-sinC) is equal to

In triangle A B C ,(sinA+sinB+sinC)/(sinA+sinB-sinC) is equal to

In triangle A B C ,(sinA+sinB+sinC)/(sinA+sinB-sinC) is equal to

if A, B, C are acute positive angles, then : ((sinA + sinB)(sinA + sinC)(sinA + sinC))/(sinA sinB sinC) is :