A massless rod BD is suspended by two identical massless strings AB and CD of equal lengths. A block of mass m is suspended at point P such that BP is equal to x, If the fundamental frequency of the left wire is twice the fundamental frequency of right wire, then the value of x is :-

A massless rod is suspended by two identical strings AB and CD of equal length. A block of mass m is suspended from point O such that BO is equal to ‘x’. Further, it is observed that the frequency of 1^st harmonic (fundamental frequency) in AB is equal to 2^nd harmonic frequency in CD. Then, length of BO is

A massless rod of length L is suspened by two identical string AB and CD of equal length. A block of mass m is suspended from point O such that BO is equal to 'x'. Further it is observed that the frequency of 1st harmonic in AB is equal to 2nd harmonic frequency in CD . 'x' is

A massless rod of length L is suspened by two identical string AB and CD of equal length. A block of mass m is suspended from point O such that BO is equal to 'x'. Further it is observed that the frequency of 1st harmonic in AB is equal to 2nd harmonic frequency in CD . 'x' is

A massless rod of length L is suspened by two identical string AB and CD of equal length. A block of mass m is suspended from point O such that BO is equal ti 'x'. Further it is obsreved that the frequency of 1st harmonic in AB is equal to 2nd harmonic frequency in CD . 'x' is

From two identical wires, a rod XY of length l is hung. A wooden block of mass m is hung at point O of the rod at a distance a from wire A. Find the value of a in the case when a tuning fork excites the fundamental note in wire A and third harmonic in wire B.

A rod PQ of length 'L' is hung from two identical wires A and B. A block of mass 'm' is hung at point R of the rod as shown in figure. The value of 'x' so that the fundamental mode in wire A is in resonance with first overtone of B is

A rod PQ of length 'L' is hung from two identical wires A and B. A block of mass 'm' is hung at point R of the rod as shown in figure. The value of 'x' so that the fundamental mode in wire A is in resonance with first overtone of B is

A wire of length 1m and mass 20g is stretched with a force of 800 N. Find the fundamental frequency. Also find the frequencies of the first two Overtones.

A wire of length 1m and mass 20g is stretched with a force of 800 N. Find the fundamental frequency. Also find the frequencies of the first two Overtones.