A lady gives a dinner party to 5 guests to be selected from nine friends. The number of ways of forming the party of 5, given that two of the friends will not attend the party together, is

A lady gives a dinner party to 5 guests to be selected from nine friends. The number of ways of forming the party of 5, given that two of the friends will not attended the party together is

A lady gives a dinner party for six guests. The number of ways in which they may be selected from among ten friends if two of the friends will not attend the party together is 112 b. 140 c. 164 d. none of these

A lady gives dinner party to six guests . The number of ways in which they may be selected from among ten friends if two of the friends , will not attend the party together is :

A lady gives a dinner party for six guests.The number of ways in which they may be selected from among ten friends if two of the friends will not attend the party together is 112 b.140 c.164 d.none of these

A lady gives a dinner party for six guest. The number of wages in which they may be selected from among 10 friends, if two of the friends will not attend the party together is

Find the number of ways in which a lady can invite 6 guests selected from 10 friends so that two of the friends will not attend the party together?

A man has 6 friends. Number of ways he can invite one or more of them to a tea party is