The coefficients of three consecutive terms of `(1+x)^(n+5)` are in the ratio 5:10:14. Then `n=` ___________.

The coefficients of three consecutive terms of (1+x)^(n+5) are in the ration 5 : 10 : 14 . Then n =

The coefficients of three consecutive terms in the expansion of (1+x)^n are in the ratio 1:7:42 , then n=

The coefficients of three consecutive terms in the expansion of (1+x)^(n) are in the ratio 1:7:42. Find n.

The coefficients of three consecutive terms in the expansion of (1+a)^(n) are in the ratio 1:7:42. Find n.

If for some positive integer n, the coefficients of three consecutive terms in the binomial expansion (1+x)^(n+5) are in the ratio 5:10:14 , then the largest coefficient in this expansion is :

If the coefficients of three consecutive terms in the expansion of (1+x)^(n) are in the ratio 1:7:42, then find the value of n.

If the coefficients of three consecutive terms in the expansion of (1+x)^(n) are in the ratio 1:7:42, then find the value of n.

The coefficients of three consecutive terms in the expansion of. (1+a)^n are in the ratio 1: 7: 42. Find n.

The coefficients of three consecutive terms in the expansion of (1+a)^n are in the ratio 1: 7 : 42. Find n.

If the coefficients of three consecutive terms in the expansion of (1 + x)^(n) are in the ratio 1 : 3 : 5, then show that n = 7.