Home
Class 11
CHEMISTRY
Some solid NH(4)HS is placed in flask co...

Some solid `NH_(4)HS` is placed in flask containing `0.5` atm of `NH_(3)`. What would be the pressure of `NH_(3)` and `H_(2)S` when equilibrium is reached.
`NH_(4)HS(g) hArr NH_(3)(g)+H_(2)S(g), K_(p)=0.11`

Promotional Banner

Similar Questions

Explore conceptually related problems

Some solid NH_(4)HS is placed in flask containing 0.5 atm of NH_(3) . What would be the pressure of NH_(3) and H_(2)S when equilibrium is reached. NH_(4)HS(s) hArr NH_(3)(g)+H_(2)S(g), K_(p)=0.11

Some acid NH_(4)HS is placed in flask containing 0.5 atm of NH_(3) . What would be pressures of NH_(3) and H_(2)S when equilibrium is reached? NH_(4)HS_((s))hArrNH_(3(g))+H_(2)S_((g)) , K_(p)=0.11

Some solid NH_4HS is placed in a flask containing 0.5 atm NH_3 . What is the equilibrium presence of NH_3 if K_p =0.11 atm^2 for the reaction NH_4HS(s) leftrightarrow NH_3(s)+H_2S(g) .

On adding NH_4HS in following equilibrium NH_4HS(s)hArr NH_3(g) +H_2S(g)

On adding NH_4HS in following equilibrium NH_4HS(s) leftrightarrow NH_3(g)+H_2S(g)

Consider the decomposition of solid NH_(4)HS in a flask containing NH_(3)(g) at a pressure of 2 atm. What will be the partial pressure of NH_(3)(g) "and" H_(2)S(g) after the equilibrium has been attained? K_(p) for the reaction is 3 .

The equilibrium pressure of NH_(4)CN(s) hArr NH_(3)(g)+HCN(g) is 2.98 atm. Calculate K_(p)