The peak value of alternating e.m.f. in a generator is given by `e_(0) =`

The r.m.s value of alternating e.m.f. is

.The peak value of an alternating e.m.f. which is given by E=E_(0) coswt is 10 volts and its frequency is 50Hz .At time t=(1)/(600) s,the instantaneous e.m.f.is

The value of alternating emf E in the given circuit will be

The value of alternating emf E in the given circuit will be

The peak value of an alternating e.m.f. is 141.4 V. What would be the reading of an a.c. voltmeter when connected across this e.m.f. ?

The peak value of an alternating emf E given by E=(E_0) cos omega t is 10V and frequency is 50 Hz. At time t=(1//600)s the instantaneous value of emf is

The peak value of an alternating emf E given by E=(E_0) cos omega t is 10V and freqency is 50 Hz. At time t=(1//600)s the instantaneous value of emf is

The peak value of an alternating emf E given by E = underset(o)(E) cos omega t is 10 V and frequency is 50 Hz . At time t = (1/600) s, the instantaneous value of emf is