The sublimation energy of `I_(2)` (solid) is 57.3 KJ/mole and enthalpy of fusion is 15.5 KJ/mole. The enthalpy of vapourisation of `I_(2)` is

The bond energy of H_(2(g)) is 436kJ/mole. The bond enthalpy of N_(2(g)) is 941.3 kJ/mole. What is the bond enthalpy of N - H if NH_3 formation energy is -46.0 kJ/mole ?

Enthalpy of vaporisation of napthalene is 48.5 kJ/mol and enthalpy of fusion of napthalene is 22.5 kJ/mol, then enthalpy of subtlimation of naphthalene will be

From the following data : Enthalpy of formation of CH_(3)CN =87.86 kJ/mol Enthalpy of formation of C_(2)H_(6)=- 83.68 kJ/mol Enthalpy of sublimation of graphite =719.65 kJ/mol enthalpy of dissociation of nitrogen =945.58 kJ/mol Enthalpy of dissociation of H_(2) = 435.14 kJ/mol C-H bond enthalpy =414.22 kJ/mol Calculate the bond enthalpy of (i) C-C , (ii) C equiv N

For a reaction, Ararr B + C , activation energy is 15 kJ/mole and enthalpy of reaction is +5kJ/mole. The activation energy for the reaction B+Crarr A is

Define: (i) Enthalpy of fusion, (ii) Enthalpy of vaporisation, (iii) Enthalpy of sublimation.