A large tank filled with water to a height `h` is to be emptied through a small hole at the bottom. The ratio of times taken for the level of water to fall from h to `(h)/(2)` and from `(h)/(2)` to zero is

A large tank filled with water to a height h is to be emptied through a small hole at the bottom. The ratio of times taken for the level of water to fall from h to h/2 and h/2 to zero is

A tank is filled with water to a height h. A hole is made at the bottom of the tank through which water can flow out. Calculate the ratio of time taken to make the level of water from h to h/4" and then "h/4" to 0."

In a container, filled with water upto a height h, a hole is made in the bottom. The velocity of water flowing out of the hole is

A large tank is filled with water to a height H . A small hole is made at the base of the tank. It takes T_(1) time to decrease the height of water to (H)/(eta) (eta gt 1) , and it takes T_(2) times to take out the rest of water. If T_(1) = T_(2) , then the value of eta is