Tangents drawn from point of intersection A of circles `x^2+y^2=4 and (x-sqrt3)^2+(y-3)^2= 4` cut the line joinihg their centres at B and C Then triangle BAC is

Tangents drawn from point of intersection A of circles x^(2)+y^(2)=4 and (x-sqrt(3))^(2)+(y-3)^(2)=4 cut the line joining their centres at B and C Then triangle BAC is

Tangents drawn from the point (4, 3) to the circle x^2+y^2-2x-4y=0 are inclined at an angle :

Tangents drawn from the point (4, 3) to the circle x^(2)+y^(2)-2x-4y=0 are inclined at an angle

Tangents drawn from the point (4, 3) to the circle x^(2)+y^(2)-2x-4y=0 are inclined at an angle

Tangents drawn from the point P(1,8) to the circle x^(2) + y^(2) - 6x - 4y -11=0 touch the circle at the points A and B. The equation of the circumcircle of the triangle PAB is:

Tangents are drawn from the point (4,3) to circle x^(2)+y^(2)=9. The area of the triangle forme by them and the line joining their point of contact is

If tangents are drawn to the circle x^(2) + y^(2) = 12 at the points of intersection with the circle x^(2) + y^(2) -5x + 3y -2 =0 , then the ordinate of the point of intersection of these tangents is

Tangents drawn from the point P(1,8) to the circle x^(2)+y^(2)-6x-4y-11=0 touch the circle at points A and B. The equation of the cricumcircle of triangle PAB is