If one angular bisector of `a(x + 1)^2 + 2h(x + 1) (y-3) + b(y-3)^2=0` is `2x-3y + 11 = 0` then equation of other angular bisector is

One of the bisector of the angle between the lines a(x-1)^2 + 2h(x-1)(y-2) + b (y-2)^2 = 0 is x + 2y - 5 = 0 . Then other bisector is (A) 2x-y=0 (B) 2x+y=0 (C) 2x+y-4=0 (D) x-2y+3=0

One of the bisector of the angle between the lines a(x-1)^2 + 2h(x-1)(y-2) + b (y-2)^2 = 0 is x + 2y - 5 = 0 . Then other bisector is (A) 2x-y=0 (B) 2x+y=0 (C) 2x+y-4=0 (D) x-2y+3=0

One of the bisector of the angle between the lines a(x-1)^2 + 2h(x-1)(y-2) + b (y-2)^2 = 0 is x + 2y - 5 = 0 . Then other bisector is (A) 2x-y=0 (B) 2x+y=0 (C) 2x+y-4=0 (D) x-2y+3=0

One of the bisector of the angle between the lines a(x-1)^2 + 2h(x-1)(y-2) + b (y-2)^2 = 0 is x + 2y - 5 = 0 . Then other bisector is (A) 2x-y=0 (B) 2x+y=0 (C) 2x+y-4=0 (D) x-2y+3=0

One bisector of the angle between the lines given by a(x-1)^(2)+2h(x-1)y+by^(2)=0 is 2x+y-2=0 . The equation of the other bisector is

One bisector of the angle between the lines given by a(x-1)^(2)+2h(x-1)y+by^(2)=0 is 2x+y-2=0 . The equation of the other bisector is

One bisector of a(x-1)^(2)+2h(x-1)y+by^(2)=0 is 2x+y-2=0 is then other bisector is

Let ABC be a triangle such that the coordinates of A are (–3, 1). Equation of the median through B is 2x + y – 3 = 0 and equation of the angular bisector of C is 7x – 4y – 1 = 0. Then match the entries of column-I with their corresponding correct entries of column-II

If 2x + y - 4= 0 is a bisector of angles between the lines a(x-1) + b(y-2) = 0, c(x-1) + d(y-2)=0 the other angular bisector is

The equation of pair of angular bisectors of (a-b)x^(2)+4hxy-(a-b)y^(2)=0 is