Equation of a circle having radius equal to twice the radius of the circle `x^2+y^2+(2p +3)x + (3-2p)y +p-3 = 0` and touching it at the origin is

The radius of the circle (p-1)x^2 + y^2 - x - py= 0 is

Find the centre and the radius of the circles 3x^(2) + 3y^(2) - 8x - 10y + 3 = 0

Find the centre and the radius of the circles 3x^(2) + 3y^(2) - 8x - 10y + 3 = 0

Find the centre and radius of the circle 3x^2 + 3y^2 - 8x - 10y + 3=0

Find the centre and radius of the circle 3x^2 + 3y^2 - 8x - 10y + 3=0

The equation of the circle having radius 3 and touching the circle x^(2) + y^(2)-4x -6y - 12 = 0 at (-1,-1) is

Find the equation of a circle of radius 5 which lies within the circle x^2 + y^2+14x + 10y- 26 = 0 and which touches the given circle at the point (- 1, 3).

The equation of a circle of radius 1 touching the circle x^2 + y^2 - 2|x| = 0 is

Find the centre and radius of equation of circle in x^(2) + y^(2) - x + 2y - 3 = 0