Two packs of 52 playing cards are shuffled together . The number of ways in which a man can be dealt 26 cards so that does not get two cards of the same suit and same denomination. (A) `^52C_26` (B) `^52C_26.2` (C) `^52C_26.2^26` (D) none of these

Two packs of 52 cards are shuffled together. The number of ways in which a man can be dealt 26 cards so that he does not get two cards of the same suit and same denomination is a. ^(52) C_(26). 2^(26) b. ^104 C_(26) c. ^(52)C_(26) d. none of these

Two packs of 52 cards are shuffled together. The number of ways in which a man can be dealt 26 cards so that he does not get two cards of the same suit and same denomination is a. ^52C_(26). 2^(26) b. ^104 C_(26) c. ^(52)C_(26) d. none of these

Two packs of 52 cards are shuffled together. The number of ways in which a man can be dealt 26 cards so that he does not get two cards of the same suit and same denomination is a.52C_(26).2^(26) b.^(104)C_(26) c..^(52)C_(26) d.none of these

Two packs of 52 cards are shuffled together. The number of ways in which a man can be dealt 26 cards so that he does not get two cards of the same suit and same denomination is a. ^52 C_(26). 2^(26) b. ^104 C_(26) c. dot^(52)C_(26) d. none of these

From a regular pack of 52 cards,6 cards are selected.The number of ways of selection such that there is at least one card of each suit and every card is of different denomination is

Find the number of ways of choosing 4 cards from a pack of 52 playing cards. How many of these Four cards are of the same suits?

What is the number of ways of choosing 4 cards from a pack of 52 cards ? In how many of these Four cards are of same suit