Prove that BS is perpendicular to PS, where P lies on the parabola `y^2 =4ax and B` is the point of intersection of tangent at P and directrix of the parabola.

The point P(9/2,6) lies on the parabola y^(2)=4ax then parameter of the point P is:

The locus of the point of intersection of perependicular tangent of the parabola y^(2) =4ax is

The locus of the point of intersection of perpendicular tangents to the parabola y^(2)=4ax is

The locus of the point of intersection of perpendicular tangents to the parabola y^(2)=4ax is

The locus of point of intersection of perpendicular tangent to parabola y^2= 4ax

Statement-1: y+b=m_(1) (x+a) and y+b=m_(2)(x+a) are perpendicular tangents to the parabola y^(2)=4ax . Statement-2: The locus of the point of intersection of perpendicular tangents to a parabola is its directrix.

Statement-1: y+b=m_(1) (x+a) and y+b=m_(2)(x+a) are perpendicular tangents to the parabola y^(2)=4ax . Statement-2: The locus of the point of intersection of perpendicular tangents to a parabola is its directrix.

Prove that the tangents drawn on the parabola y^(2)=4ax at points x = a intersect at right angle.

Prove that the tangents drawn on the parabola y^(2)=4ax at points x = a intersect at right angle.