In quadrilatcal ABCD, prove that `AB+ BC +CD+ AD<2 (BD +AC)`

In a quadrilateral ABCD, prove that : (i) AB+BC+CD gt DA (ii) AB+BC+CD+DA gt 2AC (iii) AB+BC+CD+DA gt 2BD

In cyclic quadrilateral ABCD, AD|| BC. Prove that AB = CD.

A quadrilateral ABCD is drawn to circumscribe a circle. Prove that AB+CD=AD+BC. or A circle touches all the four sides of a quadrilateral ABCD. Prove that AB+CD=BC+DA.

In quadrilateral ABCD, AB = BC = CD = AD and AC ne BD then it is a .....

In a quadrilateral ABCD, it is given that AB ||CD and the diagonals AC and BD are perpendicular to each other. Show that AD.BC >= AB. CD.

If in the cyclic quadrilateral AB||CD , then prove that AD =BC and AC=BD.

In quadrilateral ABCD, AB = AD and BC = CD. Show that angleABC= angleADC .

In a quadrilateral ABCD, it is given that AB |\|CD and the diagonals AC and BD are perpendicular to each other. Show that AD.BC >= AB. CD .

In a quadrilateral ABCD, it is given that AB |\|CD and the diagonals AC and BD are perpendicular to each other. Show that AD.BC >= AB. CD .