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If x^3+y^3=t-1/t and x^6+y^6=t^2+1/(t^2)...

If `x^3+y^3=t-1/t` and `x^6+y^6=t^2+1/(t^2)` then prove that `(d^2y)/(dx^2) = (2y)/x^2.`

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