`1/(x-2)+1/(x-3)+1/(x-4)=0`

1/((x-2)(x-4))+1/((x-4)(x-6))+1/((x-6)(x-8))+1/3=0

If (x_i , 1/x_i), i = 1, 2, 3, 4 are four distinct points on a circle, then (A) x_1 x_2 = x_3 x_4 (B) x_1 x_2 x_3 x_4 = 1 (C) x_1 + x_2 + x_3 + x_4 = 1 (D) 1/x_1 + 1/x_2 + 1/x_3 + 1/x_4 = 1

lim_(x rarr0)(sin^(-1)x-sin x)/(x^(3)) 1) (1)/(2) , 2) (1)/(3) , 3) (1)/(4) , 4) (1)/(5)

Solve : (i)" "((x-1)\(x-2)(x-3))/((x+1)(x+2)(x+3))" "(ii) " "(x^(4)+x^(2)+1)/(x^(2)+4x-5)lt0

If 0 lt x lt 1 and y=(1)/(2) x^(2) +(2)/(3) x^(3) +(3)/(4) x^(4) + ……. , then the vlaue of e^(1+y) at x=(1)/(2) is :

lim_(x-> -1) (x+1)/(sqrt(x^2 + 3) -2) = (1) -2 (2) 1/2 (3) 2 (4) 0

The function f(x)=(|x|)/(x),x>0 is :- (1) 0 (2) 1 (3) 2 (4) -2

If f(x)=(1+x)(1+x^2)(1+x^3)(1+x^4) , then f'(0)=1

(lim)_(x rarr0)((1-cos2x)(3+cos x)/(x tan4x)) is equal to (1)(1)/(2)(2)1(3)2(4)-(1)/(4)